JEE Main 2023 · PhysicsMultiple choiceSingle correctMediumMulti-step

JEE Main 6 April 2023, Shift 1, Physics Q39

Question 39 of 90 in this shift, Physics question 9 of 30, Section A.

A particle is moving with constant speed in a circular path. When the particle turns by an angle

90^\circ

, the ratio of instantaneous velocity to its average velocity is

\pi : x\sqrt2

. The value of

x

will be -

(1)7
(2)5
(3)2Official answer
(4)1

Official answer

Option 3

NTA final key.

Chapter: Motion in a Plane
Topic: Kinematics in 2D
Idea tested: Uniform Circular Motion

Same topic in other shifts

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.