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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceDiagram basedMediumMulti-step

JEE Main 30 June 2022, Shift 1, Chemistry Q77

Question 77 of 90 in this shift, Chemistry question 17 of 30, Section A.

[structure: A + CH3CH2OH\mathrm{CH_3CH_2OH} ⟶\longrightarrow benzene ring] →(iii) HCl(i) H2SO4 (oleum), Δ (ii) NaOH\xrightarrow[\text{(iii) HCl}]{\text{(i) } \mathrm{H_2SO_4}\text{ (oleum), }\Delta\ \text{(ii) NaOH}} B Consider the above reaction sequence. Identify the component A and component B :

The figure, in words

Reaction scheme with benzene ring drawn as the product of A + CH3CH2OH; options pair a formula with a drawn substituted benzene ring.
  1. (1)A=C6H5NH2\mathrm{C_6H_5NH_2} ; B = [benzene ring bearing Cl]
  2. (2)A = C6H5N2+Cl−\mathrm{C_6H_5N_2^{+}Cl^{-}} ; B = [benzene ring bearing OH]Official answer
  3. (3)A = [benzene ring bearing Cl] ; B = C6H5NH2\mathrm{C_6H_5NH_2}
  4. (4)A = [benzene ring bearing OH] ; B = C6H5N2+Cl−\mathrm{C_6H_5N_2^{+}Cl^{-}}

Official answer

Option 2

NTA final key.

Chapter
Amines