JEE Main 2022 (30 Jun, Shift 1) Maths Q13: Straight Lines

Question

Let $\alpha_1, \alpha_2$ ($\alpha_1 < \alpha_2$) be the values of $\alpha$ for the points $(\alpha, -3)$, $(2, 0)$ and $(1, \alpha)$ to be collinear. Then the equation of the line, passing through $(\alpha_1, \alpha_2)$ and making an angle of $\frac{\pi}{3}$ with the positive direction of the $x$-axis, is :

Accepted Answer

Option 2: $\sqrt{3}x - y + \sqrt{3} + 3 = 0$

Answer

$x - \sqrt{3}y - 3\sqrt{3} + 1 = 0$

Answer

$\sqrt{3}x - y + \sqrt{3} + 3 = 0$

Answer

$x - \sqrt{3}y + 3\sqrt{3} + 1 = 0$

Answer

$\sqrt{3}x - y + \sqrt{3} - 3 = 0$

JEE Main 30 June 2022, Shift 1, Maths Q13