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Saturday, 31 October

JEE Main 2022 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 29 June 2022, Shift 2, Chemistry Q89

Question 89 of 90 in this shift, Chemistry question 29 of 30, Section B.

In the given reaction, [figure: six-membered ring of single bonds with an HO group attached; reagents over the arrow: (i) K2Cr2O7\mathrm{K_2Cr_2O_7}, (ii) C6H5MgBr\mathrm{C_6H_5MgBr}, (iii) H2O\mathrm{H_2O}, (iv) H+\mathrm{H^{+}}, heat; product 'X' Major Product] the number of sp2sp^2 hybridised carbon(s) in compound ‘X’ is ___.

The figure, in words

Reaction scheme: a six-membered saturated ring with an HO group on one carbon, arrow with four steps (i) K2Cr2O7 (ii) C6H5MgBr (iii) H2O (iv) H+, heat, giving 'X' (Major Product).

Official answer

8

NTA final key.

Chapter
Alcohols, Phenols and Ethers
Topic
Alcohols and Phenols
Idea tested
Selective Alcohol Oxidation

Same idea in other shifts

Asked 2× in all
  1. 24 Feb 2021, Shift 1 · Q45Identify products A and B. [figure]…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.