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Saturday, 31 October

JEE Main 2022 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 29 June 2022, Shift 2, Maths Q27

Question 27 of 90 in this shift, Maths question 27 of 30, Section B.

Let the coefficients of x−1x^{-1} and x−3x^{-3} in the expansion of (2x15−1x15)15\left(2x^{\frac{1}{5}} - \frac{1}{x^{\frac{1}{5}}}\right)^{15}, x>0x > 0, be mm and nn respectively. If rr is a positive integer such that mn2=15Cr⋅2rmn^2 = {}^{15}C_r \cdot 2^r, then the value of rr is equal to ___.

Official answer

5

NTA final key.

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.