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JEE Main 2022 · ChemistryNumerical answerNumerical valueEasyMulti-step

JEE Main 29 June 2022, Shift 1, Chemistry Q90

Question 90 of 90 in this shift, Chemistry question 30 of 30, Section B.

C6H12O6→ZymaseA→ΔNaOIB+CHI3\mathrm{C_6H_{12}O_6 \xrightarrow{Zymase} A \xrightarrow[\Delta]{NaOI} B + CHI_3} The number of carbon atoms present in the product B is ____________.

Official answer

1

NTA final key (2022 Session 1).