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Friday, 9 October

JEE Main 2022 · ChemistryMultiple choiceOtherEasyApplication

JEE Main 29 June 2022, Shift 1, Chemistry Q76

Question 76 of 90 in this shift, Chemistry question 16 of 30, Section A.

[reactions: aniline →H2OBr2 (excess)\xrightarrow[\mathrm{H_2O}]{\mathrm{Br_2\,(excess)}} A (Major Product); aniline →(i) (CH3CO)2O; (ii) Br2, CH3COOH; (iii) HCl\xrightarrow{\text{(i) }(\mathrm{CH_3CO})_2\mathrm{O}\text{; (ii) }\mathrm{Br_2,\,CH_3COOH}\text{; (iii) HCl}} B (Major Product)] Consider the above reactions, the product A and product B respectively are

The figure, in words

Two reaction schemes starting from aniline (benzene ring with NH2): left with excess Br2/H2O giving A; right with (i) (CH3CO)2O, (ii) Br2/CH3COOH, (iii) HCl giving B. Options show pairs of brominated anilines.
  1. (1)[figure: A = 4-bromoaniline and B = 4-bromoaniline]
  2. (2)[figure: A = 2,4,6-tribromoaniline and B = 2,4,6-tribromoaniline]
  3. (3)[figure: A = 2,4,6-tribromoaniline and B = 4-bromoaniline]Official answer
  4. (4)[figure: A = 4-bromoaniline and B = 2,4,6-tribromoaniline]

Official answer

Option 3

NTA final key (2022 Session 1).

Chapter
Amines
Topic
Amines