JEE Main 2022 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 29 June 2022, Shift 1, Physics Q54

Question 54 of 90 in this shift, Physics question 24 of 30, Section B.

A body is performing simple harmonic with an amplitude of 10 cm. The velocity of the body was tripled by air Jet when it is at 5 cm from its mean position. The new amplitude of vibration is

\sqrt{x}

cm. The value of

x

is ____________.

Official answer

700

NTA final key (2022 Session 1).

Chapter: Oscillations
Topic: Energy in SHM
Idea tested: Energy Change from Instantaneous Impulse

Same topic in other shifts

All Energy in SHM questions

6 Apr 2026, Shift 2 · Q36A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium position the mass is further pulled down by 2 mm and…MediumSingle correct
29 Jan 2024, Shift 1 · Q54When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is…EasyNumerical value
11 Apr 2023, Shift 1 · Q42The variation of kinetic energy (KE) of a particle executing simple harmonic motion with the displacement ( $x$ ) starting from mean…EasyDiagram basedHas a figure
13 Apr 2023, Shift 2 · Q40A particle executes SHM of amplitude A. The distance from the mean position when its's kinetic energy becomes equal to its potential…EasySingle correct
2 Apr 2017 (offline) · Q12A particle is executing simple harmonic motion with a time period T. At time $t=0$ , it is at its position of equilibrium. The kinetic…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.