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Saturday, 10 October

JEE Main 2022 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 29 June 2022, Shift 1, Maths Q4

Question 4 of 90 in this shift, Maths question 4 of 30, Section A.

Let f:R→Rf: \mathbf{R} \to \mathbf{R} be a function defined by : f(x)={max⁡t≤x{t3−3t};  x≤2x2+2x−6;  2<x<3[x−3]+9;  3≤x≤52x+1;  x>5f(x) = \begin{cases} \max_{t \le x}\{t^3 - 3t\} & ; \; x \le 2 \\ x^2 + 2x - 6 & ; \; 2 < x < 3 \\ [x - 3] + 9 & ; \; 3 \le x \le 5 \\ 2x + 1 & ; \; x > 5 \end{cases} where [t][t] is the greatest integer less than or equal to tt. Let mm be the number of points where ff is not differentiable and I=∫−22f(x) dxI = \int_{-2}^{2} f(x)\,dx. Then the ordered pair (m,I)(m, I) is equal to :
  1. (1)(3,274)\left(3, \frac{27}{4}\right)
  2. (2)(3,234)\left(3, \frac{23}{4}\right)
  3. (3)(4,274)\left(4, \frac{27}{4}\right)Official answer
  4. (4)(4,234)\left(4, \frac{23}{4}\right)

Official answer

Option 3

NTA final key (2022 Session 1).