JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 29 June 2022, Shift 1, Physics Q38

Question 38 of 90 in this shift, Physics question 8 of 30, Section A.

A particle of mass 500 gm is moving in a straight line with velocity

v = bx^{5/2}

. The work done by the net force during its displacement from

x = 0

x = 4

m is : (Take

b = 0.25\ \mathrm{m^{-3/2}\,s^{-1}}

(1)2 J
(2)4 J
(3)8 J
(4)16 JOfficial answer

Official answer

Option 4

NTA final key (2022 Session 1).

Chapter: Work, Energy and Power
Topic: Work and Kinetic Energy
Idea tested: Work-Energy Theorem

Same idea in other shifts

Asked 7× in all

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2 Apr 2017 (offline) · Q4A time dependent force $F=6t$ acts on a particle of mass 1 kg. If the particle starts from rest, the work done by the force during the…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.