JEE Main 2022 (29 Jun, Shift 1) Maths Q15: The domain of…

Question

The domain of the function $\cos^{-1}\left(\frac{2\sin^{-1}\left(\frac{1}{4x^2 - 1}\right)}{\pi}\right)$ is :

Accepted Answer

Option 4: $\left(-\infty, \frac{-1}{\sqrt{2}}\right] \cup \left[\frac{1}{\sqrt{2}}, \infty\right) \cup \{0\}$

Answer

$\mathbf{R} - \left\{-\frac{1}{2}, \frac{1}{2}\right\}$

Answer

$(-\infty, -1] \cup [1, \infty) \cup \{0\}$

Answer

$\left(-\infty, \frac{-1}{2}\right) \cup \left(\frac{1}{2}, \infty\right) \cup \{0\}$

Answer

$\left(-\infty, \frac{-1}{\sqrt{2}}\right] \cup \left[\frac{1}{\sqrt{2}}, \infty\right) \cup \{0\}$

JEE Main 29 June 2022, Shift 1, Maths Q15