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Friday, 9 October

JEE Main 2022 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 29 June 2022, Shift 1, Maths Q10

Question 10 of 90 in this shift, Maths question 10 of 30, Section A.

Let A=[aij]A = [a_{ij}] be a square matrix of order 3 such that aij=2j−ia_{ij} = 2^{j-i}, for all i,j=1,2,3i, j = 1, 2, 3. Then, the matrix A2+A3+…+A10A^2 + A^3 + \ldots + A^{10} is equal to :
  1. (1)(310−32)A\left(\frac{3^{10} - 3}{2}\right)AOfficial answer
  2. (2)(310−12)A\left(\frac{3^{10} - 1}{2}\right)A
  3. (3)(310+12)A\left(\frac{3^{10} + 1}{2}\right)A
  4. (4)(310+32)A\left(\frac{3^{10} + 3}{2}\right)A

Official answer

Option 1

NTA final key (2022 Session 1).

Chapter
Matrices