JEE Main 2022 · ChemistryMultiple choiceSingle correctEasyRecall

JEE Main 28 June 2022, Shift 2, Chemistry Q79

Question 79 of 90 in this shift, Chemistry question 19 of 30, Section A.

When sugar ‘X’ is boiled with dilute

\mathrm{H_2SO_4}

in alcoholic solution, two isomers ‘A’ and ‘B’ are formed. ‘A’ on oxidation with

\mathrm{HNO_3}

yields saccharic acid where as ‘B’ is laevorotatory. The compound ‘X’ is :

(1)Maltose
(2)SucroseOfficial answer
(3)Lactose
(4)Strach

Official answer

Option 2

NTA final key.

Chapter: Biomolecules
Topic: Carbohydrates
Idea tested: Sucrose Structure and Linkage

Same idea in other shifts

Asked 4× in all

25 Jul 2022, Shift 2 · Q78Glycosidic linkage between C1 of $\alpha$ -glucose and C2 of $\beta$ –fructose is found inEasySingle correct
26 Aug 2021, Shift 2 · Q49Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Sucrose is a…EasyAssertion–reason
26 Feb 2021, Shift 2 · Q48Match List-I with List-II. List-I | List-II (a) Sucrose | (i) $\beta$ -D-Galactose and $\beta$ -D-Glucose (b) Lactose | (ii)…EasyMatch the list

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.