JEE Main 2022 (28 Jun, Shift 2) Maths Q7: Integrals

Question

Let $f : \mathbf{R} 	o \mathbf{R}$ be a differentiable function such that $f\left(\frac{\pi}{4}ight)=\sqrt{2}$, $f\left(\frac{\pi}{2}ight)=0$ and $f'\left(\frac{\pi}{2}ight)=1$
and let $g(x)=\int_x^{\pi/4}(f'(t)\,\mathrm{sect}+\mathrm{tant}\,\mathrm{sect}\,f(t))\,dt$ for $x \in \left[\frac{\pi}{4}, \frac{\pi}{2}ight)$. Then $\lim_{x	o\left(\frac{\pi}{2}ight)^-} g(x)$ is equal to :

Accepted Answer

Option 2: 3

Answer

2

Answer

3

Answer

4

Answer

$-3$

JEE Main 28 June 2022, Shift 2, Maths Q7