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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceSingle correctMediumCalculation

JEE Main 28 June 2022, Shift 2, Chemistry Q64

Question 64 of 90 in this shift, Chemistry question 4 of 30, Section A.

A student needs to prepare a buffer solution of propanoic acid and its sodium salt with pH 4. The ratio of [CH3CH2COO−][CH3CH2COOH]\frac{[\mathrm{CH_3CH_2COO^-}]}{[\mathrm{CH_3CH_2COOH}]} required to make buffer is __________. Given : Ka(CH3CH2COOH)=1.3×10−5\mathrm{K_a(CH_3CH_2COOH)} = 1.3\times10^{-5}
  1. (1)0.03
  2. (2)0.13Official answer
  3. (3)0.23
  4. (4)0.33

Official answer

Option 2

NTA final key.