JEE Main 2022 (28 Jun, Shift 2) Physics Q32: A ball is…

Question

A ball is spun with angular acceleration $\alpha = 6t^2 - 2t$ where t is in second and $\alpha$ is in rads$^{-2}$. At t=0, the ball has angular velocity of 10 rads$^{-1}$ and angular position of 4 rad. The most appropriate expression for the angular position of the ball is :

Accepted Answer

Option 2: $\frac{t^4}{2} - \frac{t^3}{3} + 10t + 4$

Answer

$\frac{3}{2}t^4 - t^2 + 10t$

Answer

$\frac{t^4}{2} - \frac{t^3}{3} + 10t + 4$

Answer

$\frac{2t^4}{3} - \frac{t^3}{6} + 10t + 12$

Answer

$2t^4 - \frac{t^3}{2} + 5t + 4$

JEE Main 28 June 2022, Shift 2, Physics Q32