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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 28 June 2022, Shift 2, Maths Q18

Question 18 of 90 in this shift, Maths question 18 of 30, Section A.

The value of lim⁡n→∞6tan⁡{∑r=1ntan⁡−1(1r2+3r+3)}\lim_{n\to\infty} 6\tan\left\{\sum_{r=1}^{n}\tan^{-1}\left(\frac{1}{r^2+3r+3}\right)\right\} is equal to :
  1. (1)1
  2. (2)2
  3. (3)3Official answer
  4. (4)6

Official answer

Option 3

NTA final key.