JEE Main 2022 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 28 June 2022, Shift 1, Chemistry Q87

Question 87 of 90 in this shift, Chemistry question 27 of 30, Section B.

The quantity of electricity in Faraday needed to reduce 1 mol of

\mathrm{Cr_2O_7^{2-}}

\mathrm{Cr^{3+}}

is ________

Official answer

NTA final key.

Chapter: Electrochemistry
Topic: Faraday's Laws of Electrolysis
Idea tested: Charge-Mole Relationship

Same idea in other shifts

Asked 4× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.