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JEE Main 27 June 2022, Shift 2, Physics Q36

Question 36 of 90 in this shift, Physics question 6 of 30, Section A.

Four spheres each of mass

m

form

a

square of side

d

(as shown in figure). A fifth sphere of mass

M

is situated at the centre of square. The total gravitational potential energy of the system is :

The figure, in words

A square drawn with a small circle at each of its four corners, each labelled m; a larger circle labelled M at the centre of the square. A double-headed arrow along the bottom side between the two bottom corner circles is labelled d.

(1) $-\frac{Gm}{d}\left[(4+\sqrt{2})m + 4\sqrt{2}M\right]$ Official answer
(2) $-\frac{Gm}{d}\left[(4+\sqrt{2})M + 4\sqrt{2}m\right]$
(3) $-\frac{Gm}{d}\left[3m^{2} + 4\sqrt{2}M\right]$
(4) $-\frac{Gm}{d}\left[6m^{2} + 4\sqrt{2}M\right]$

Official answer

Option 1

NTA final key.

Chapter: Gravitation
Topic: Gravitational Potential
Idea tested: Potential Energy of Systems

JEE Main 27 June 2022, Shift 2, Physics Q36

Same idea in other shifts