JEE Main 2022 · ChemistryMultiple choiceDiagram basedHardMulti-step
JEE Main 27 June 2022, Shift 1, Chemistry Q79
Question 79 of 90 in this shift, Chemistry question 19 of 30, Section A.
L-isomer of a compound ‘A’ () gives a positive test with . Treatment of ‘A’ with acetic anhydride yields triacetate derivative. Compound ‘A’ produces an optically active compound (B) and an optically inactive compound (C) on treatment with bromine water and respectively. Compound (A) is :
The figure, in words
All four options are Fischer projections drawn with CHO at the top, CH2OH at the bottom and two stereocentres between, differing only in which side (left/right) the OH and H are drawn on each of the two middle carbons.- (1)[figure: Fischer projection, CHO at top and at bottom; the two middle carbons carry HO on the left and H on the right (upper), HO on the left and H on the right (lower)]Official answer
- (2)[figure: Fischer projection, CHO at top and at bottom; upper middle carbon has H on the left and OH on the right, lower middle carbon has HO on the left and H on the right]
- (3)[figure: Fischer projection, CHO at top and at bottom; upper middle carbon has H on the left and OH on the right, lower middle carbon has H on the left and OH on the right]
- (4)[figure: Fischer projection, CHO at top and at bottom; upper middle carbon has HO on the left and H on the right, lower middle carbon has H on the left and OH on the right]
Official answer
Option 1
NTA final key.
- Chapter
- Biomolecules
- Topic
- Carbohydrates
- Idea tested
- Selective Oxidation of Monosaccharides