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JEE Main 2022 · ChemistryMultiple choiceSingle correctMediumRecall

JEE Main 27 June 2022, Shift 1, Chemistry Q68

Question 68 of 90 in this shift, Chemistry question 8 of 30, Section A.

\mathrm{BeCl_2}

reacts with

\mathrm{LiAlH_4}

to give :

(1)Be + $\mathrm{Li[AlCl_4]}$ + $\mathrm{H_2}$
(2)Be + $\mathrm{AlH_3}$ + LiCl + HCl
(3) $\mathrm{BeH_2}$ + LiCl + $\mathrm{AlCl_3}$ Official answer
(4) $\mathrm{BeH_2}$ + $\mathrm{Li[AlCl_4]}$

Official answer

Option 3

NTA final key.

Chapter: The s-Block Elements
Topic: s-Block Elements
Idea tested: Nature of s-Block Hydrides

Same idea in other shifts

Asked 2× in all

26 Jul 2022, Shift 1 · Q66Reaction of $\mathrm{BeCl_2}$ with $\mathrm{LiAlH_4}$ gives : (A) $\mathrm{AlCl_3}$ (B) $\mathrm{BeH_2}$ (C) LiH (D) LiCl (E)…MediumOther

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.