JEE Main 2022 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 27 June 2022, Shift 1, Maths Q21

Question 21 of 90 in this shift, Maths question 21 of 30, Section B.

Let

f: \mathbf{R} \rightarrow \mathbf{R}

be a function defined by

f(x)=\frac{2e^{2x}}{e^{2x}+e}

. Then

f\left(\frac{1}{100}\right)+f\left(\frac{2}{100}\right)+f\left(\frac{3}{100}\right)+\ldots+f\left(\frac{99}{100}\right)

is equal to ____________.

Official answer

NTA final key.