/

Learn

Saturday, 31 October

/

JEE Main 2022 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 26 June 2022, Shift 1, Maths Q6

Question 6 of 90 in this shift, Maths question 6 of 30, Section A.

\lim_{x \to \frac{1}{\sqrt{2}}} \frac{\sin(\cos^{-1}x) - x}{1 - \tan(\cos^{-1}x)}

is equal to :

(1) $\sqrt{2}$
(2) $-\sqrt{2}$
(3) $\frac{1}{\sqrt{2}}$
(4) $-\frac{1}{\sqrt{2}}$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Limits and Derivatives
Topic: L'Hopital's Rule
Idea tested: L'Hopital with Inverse Trigonometric Functions

Same idea in other shifts

Asked 2× in all

1 Feb 2024, Shift 1 · Q26Let $\{x\}$ denote the fractional part of $x$ and $f(x)=\frac{\cos^{-1}(1-\{x\}^2)\sin^{-1}(1-\{x\})}{\{x\}-\{x\}^3}$ , $x\neq0$ . If L and…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.