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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 26 June 2022, Shift 1, Physics Q45

Question 45 of 90 in this shift, Physics question 15 of 30, Section A.

If Electric field intensity of a uniform plane electro magnetic wave is given as E=−301.6 sin⁡(kz−ωt) a^x+452.4 sin⁡(kz−ωt) a^y VmE=-301.6\,\sin(kz-\omega t)\,\hat{a}_x+452.4\,\sin(kz-\omega t)\,\hat{a}_y\ \frac{V}{m}. Then, magnetic intensity 'H' of this wave in Am−1\mathrm{Am^{-1}} will be : [Given : Speed of light in vacuum c=3×108 ms−1c=3\times10^{8}\ \mathrm{ms^{-1}}, Permeability of vacuum μ0=4π×10−7 NA−2\mu_0=4\pi\times10^{-7}\ \mathrm{NA^{-2}}]
  1. (1)+0.8 sin⁡(kz−ωt) a^y+0.8 sin⁡(kz−ωt) a^x+0.8\,\sin(kz-\omega t)\,\hat{a}_y+0.8\,\sin(kz-\omega t)\,\hat{a}_x .
  2. (2)+1.0×10−6 sin⁡(kz−ωt) a^y+1.5×10−6 (kz−ωt) a^x+1.0\times10^{-6}\,\sin(kz-\omega t)\,\hat{a}_y+1.5\times10^{-6}\,(kz-\omega t)\,\hat{a}_x
  3. (3)−0.8 sin⁡(kz−ωt) a^y−1.2 sin⁡(kz−ωt) a^x-0.8\,\sin(kz-\omega t)\,\hat{a}_y-1.2\,\sin(kz-\omega t)\,\hat{a}_xOfficial answer
  4. (4)−1.0×10−6 sin⁡(kz−ωt) a^y−1.5×10−6 sin⁡(kz−ωt) a^x-1.0\times10^{-6}\,\sin(kz-\omega t)\,\hat{a}_y-1.5\times10^{-6}\,\sin(kz-\omega t)\,\hat{a}_x

Official answer

Option 3

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.