JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 25 June 2022, Shift 2, Physics Q42

Question 42 of 90 in this shift, Physics question 12 of 30, Section A.

A sinusoidal voltage

V(t)

= 210 sin 3000

t

volt is applied to a series LCR circuit in which

L

= 10

mH

C

=25 µ

F

and

R

= 100

\Omega

. The phase difference (

\Phi

)between the applied voltage and resultant current will be :

(1) $\tan^{-1}(0.17)$ Official answer
(2) $\tan^{-1}(9.46)$
(3) $\tan^{-1}(0.30)$
(4) $\tan^{-1}(13.33)$

Official answer

Option 1

NTA final key.

Chapter: Alternating Current
Topic: Phasor Diagrams
Idea tested: Impedance Triangle Construction

Same idea in other shifts

Asked 9× in all

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5 Apr 2024, Shift 1 · Q57An ac source is connected in given series LCR circuit. The rms potential difference across the capacitor of $20\ \mu\mathrm{F}$ is…MediumNumerical valueHas a figure
9 Apr 2024, Shift 1 · Q43A bulb and a capacitor are connected in series across an ac supply. A dielectric is then placed between the plates of the capacitor. The…MediumSingle correct
27 Jul 2022, Shift 2 · Q44A series LCR circuit has L = 0.01 H, R = 10 $\Omega$ and C = 1 $\mu$ F and it is connected to ac voltage of amplitude ( $\mathrm{V_m}$ ) 50…MediumSingle correct
28 Jun 2022, Shift 1 · Q54An AC source is connected to an inductance of 100 mH, a capacitance of 100 $\mu$ F and a resistance of 120 $\Omega$ as shown in figure.…MediumNumerical valueHas a figure
3 Sep 2020, Shift 1 · Q15A 750 Hz, 20 V (rms) source is connected to a resistance of 100 $\Omega$ , an inductance of 0.1803 H and a capacitance of 10 $\mu$ F all in…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.