JEE Main 2022 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 25 June 2022, Shift 1, Chemistry Q89

Question 89 of 90 in this shift, Chemistry question 29 of 30, Section B.

[\mathrm{Cu(H_2O)_4}]^{2+}

absorbs a light of wavelength 600 nm for d-d transition, then the value of octahedral crystal field splitting energy for

[\mathrm{Cu(H_2O)_6}]^{2+}

will be __________

\times 10^{-21}

J. [Nearest integer] (Given :

h = 6.63 \times 10^{-34}

Js and

c = 3.08 \times 10^{8}\ \mathrm{ms^{-1}}

)

Official answer

746

NTA final key.

Chapter: Coordination Compounds
Topic: Crystal Field Theory
Idea tested: Octahedral Field Splitting

Same idea in other shifts

Asked 4× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.