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Saturday, 31 October

JEE Main 2022 · ChemistryNumerical answerNumerical valueMediumCalculation

JEE Main 25 June 2022, Shift 1, Chemistry Q86

Question 86 of 90 in this shift, Chemistry question 26 of 30, Section B.

The standard free energy change (ΔG∘\Delta \mathrm{G^\circ}) for 50% dissociation of N2O4\mathrm{N_2O_4} into NO2\mathrm{NO_2} at 27°C and 1 atm pressure is −x J mol−1-x\ \mathrm{J\ mol^{-1}}. The value of xx is __________. (Nearest Integer) [Given : R=8.31 J K−1 mol−1\mathrm{R} = 8.31\ \mathrm{J\ K^{-1}\ mol^{-1}}, log⁡1.33=0.1239\log 1.33 = 0.1239 ln⁡10=2.3\ln 10 = 2.3]

Official answer

710

NTA final key.