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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyConceptual

JEE Main 25 June 2022, Shift 1, Physics Q31

Question 31 of 90 in this shift, Physics question 1 of 30, Section A.

If Z = A2B3C4\frac{A^2B^3}{C^4}, then the relative error in Z will be :
  1. (1)ΔAA+ΔBB+ΔCC\frac{\Delta A}{A}+\frac{\Delta B}{B}+\frac{\Delta C}{C}
  2. (2)2 ΔAA+3 ΔBB−4 ΔCC\frac{2\,\Delta A}{A}+\frac{3\,\Delta B}{B}-\frac{4\,\Delta C}{C}
  3. (3)2 ΔAA+3 ΔBB+4 ΔCC\frac{2\,\Delta A}{A}+\frac{3\,\Delta B}{B}+\frac{4\,\Delta C}{C}Official answer
  4. (4)ΔAA+ΔBB−ΔCC\frac{\Delta A}{A}+\frac{\Delta B}{B}-\frac{\Delta C}{C}

Official answer

Option 3

NTA final key.

Chapter
Units and Measurements
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.