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Saturday, 31 October

JEE Main 2022 · ChemistryNumerical answerNumerical valueEasyCalculation

JEE Main 24 June 2022, Shift 2, Chemistry Q84

Question 84 of 90 in this shift, Chemistry question 24 of 30, Section B.

The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1750 Ω\Omega. If the conductivity of 0.01M KCl solution at 298 K is 0.152 ×\times 10−3^{-3} S cm−1^{-1}, then the cell constant of the conductivity cell is ________ ×\times 10−3^{-3}cm−1^{-1}.

Official answer

266

NTA final key.

Chapter
Electrochemistry
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.