JEE Main 2022 (24 Jun, Shift 2) Physics Q41: Potential…

Question

Potential energy as a function of $r$ is given by $U=\frac{A}{r^{10}}-\frac{B}{r^{5}}$, where $r$ is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be :

Accepted Answer

Option 3: $\left(\frac{2A}{B}\right)^{\frac{1}{5}}$

Answer

$\left(\frac{A}{B}\right)^{\frac{1}{5}}$

Answer

$\left(\frac{B}{A}\right)^{\frac{1}{5}}$

Answer

$\left(\frac{2A}{B}\right)^{\frac{1}{5}}$

Answer

$\left(\frac{B}{2A}\right)^{\frac{1}{5}}$

JEE Main 24 June 2022, Shift 2, Physics Q41

Same idea in other shifts