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Friday, 9 October

JEE Main 2022 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 24 June 2022, Shift 1, Physics Q54

Question 54 of 90 in this shift, Physics question 24 of 30, Section B.

As shown in the figure an inductor of inductance 200 mH is connected to an AC source of emf 220 V and frequency 50 Hz. The instantaneous voltage of the source is 0 V when the peak value of current is aπ\frac{\sqrt{a}}{\pi} A. The value of a is ______.

The figure, in words

Circuit: inductor L = 200 mH connected in a loop with an AC source.

Official answer

242

NTA final key (2022 Session 1).

Chapter
Alternating Current
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.