Learn

Friday, 9 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctHardMulti-step

JEE Main 24 June 2022, Shift 1, Physics Q35

Question 35 of 90 in this shift, Physics question 5 of 30, Section A.

A projectile is projected with velocity of 25 m/s at an angle θ\theta with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of θ\theta will be : [use g=10 m/s2g=10\ \mathrm{m/s^2}]
  1. (1)12sin⁡−1(5t24R)\frac{1}{2}\sin^{-1}\left(\frac{5t^2}{4R}\right)
  2. (2)12sin⁡−1(4R5t2)\frac{1}{2}\sin^{-1}\left(\frac{4R}{5t^2}\right)
  3. (3)tan⁡−1(4t25R)\tan^{-1}\left(\frac{4t^2}{5R}\right)
  4. (4)cot⁡−1(R20t2)\cot^{-1}\left(\frac{R}{20t^2}\right)Official answer

Official answer

Option 4

NTA final key (2022 Session 1).