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Friday, 9 October

JEE Main 2022 · MathsMultiple choiceSingle correctMediumApplication

JEE Main 24 June 2022, Shift 1, Maths Q15

Question 15 of 90 in this shift, Maths question 15 of 30, Section A.

Let λx−2y=μ\lambda x-2y=\mu be a tangent to the hyperbola a2x2−y2=b2a^2x^2-y^2=b^2. Then (λa)2−(μb)2\left(\frac{\lambda}{a}\right)^2-\left(\frac{\mu}{b}\right)^2 is equal to :
  1. (1)−2-2
  2. (2)−4-4
  3. (3)2
  4. (4)4Official answer

Official answer

Option 4

NTA final key (2022 Session 1).