Learn

Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceOtherMediumConceptual

JEE Main 30 July 2022, Shift 2, Chemistry Q34

Question 34 of 90 in this shift, Chemistry question 4 of 30, Section A.

Freundlich's adsorption isotherm (in terms of concentration) is given by the expression; xm=K⋅C1/n\frac{x}{m}=\mathrm{K}\cdot\mathrm{C}^{1/n}. The possible conclusions that can be drawn from the expression are : (A) When 1n=1\frac{1}{n}=1, the adsorption is directly proportional to concentration. (B) When 1n=0\frac{1}{n}=0, the adsorption is independent of concentration. (C) When n = 0, a plot of x/mx/m vs C is a line parallel to x-axis (D) When n = 0, a plot of x/mx/m vs C is a curve. Choose the correct option from the following :
  1. (1)(A) and (B) only
  2. (2)(B) and (D) only
  3. (3)(B), (C) and (D) only
  4. (4)(A), (B) and (C) onlyOfficial answer

Official answer

Option 4

NTA final key.

Chapter
Surface Chemistry
Topic
Adsorption
Idea tested
Limits of Freundlich Exponent (1/n)

Same idea in other shifts

Asked 2× in all
  1. 4 Aug 2021, Shift 1 · Q34Graph between log⁡xm\log\frac{x}{m}, ('x' is mass of gas adsorbed and 'm' is the mass of adsorbent) versus log P (P-pressure of gas adsorbed)…MediumDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.