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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 29 July 2022, Shift 2, Physics Q48

Question 48 of 90 in this shift, Physics question 18 of 30, Section A.

The vertical component of the earth's magnetic field is 6×10−56\times10^{-5} T at any place where the angle of dip is 37∘37^\circ. The earth's resultant magnetic field at that place will be (Given tan⁡37∘=34\tan 37^\circ=\frac{3}{4})
  1. (1)8×10−58\times10^{-5} T
  2. (2)6×10−56\times10^{-5} T
  3. (3)5×10−45\times10^{-4} T
  4. (4)1×10−41\times10^{-4} TOfficial answer

Official answer

Option 4

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 12 Apr 2023, Shift 1 · Q51A compass needle oscillates 20 times per minute at a place where the dip is 30∘30^\circ and 30 times per minute where the dip is…HardNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.