JEE Main 2022 (29 Jul, Shift 2) Physics Q38: Phasor Diagrams

Question

A circuit element X when connected to an a.c. supply of peak voltage 100 V gives a peak current of 5 A which is in phase with the voltage. A second element Y when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by

\frac{\pi}{2}

. If X and Y are connected in series to the same supply, what will be the rms value of the current in ampere?

(1) $\frac{10}{\sqrt{2}}$
(2) $\frac{5}{\sqrt{2}}$
(3) $5\sqrt{2}$
(4) $\frac{5}{2}$ Official answer

Official answer

Option 4

NTA final key.

Accepted Answer

Option 4: $\frac{5}{2}$

Answer

$\frac{10}{\sqrt{2}}$

Answer

$\frac{5}{\sqrt{2}}$

Answer

$5\sqrt{2}$

Answer

$\frac{5}{2}$

JEE Main 29 July 2022, Shift 2, Physics Q38

Same idea in other shifts