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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 29 July 2022, Shift 2, Maths Q10

Question 10 of 90 in this shift, Maths question 10 of 30, Section A.

Let y=y(x)y=y(x) be the solution curve of the differential equation dydx+(2x2+11x+13x3+6x2+11x+6)y=(x+3)x+1\frac{dy}{dx}+\left(\frac{2x^2+11x+13}{x^3+6x^2+11x+6}\right)y=\frac{(x+3)}{x+1}, x>−1x>-1, which passes through the point (0,1)(0, 1). Then y(1)y(1) is equal to :
  1. (1)12\frac{1}{2}
  2. (2)32\frac{3}{2}Official answer
  3. (3)52\frac{5}{2}
  4. (4)72\frac{7}{2}

Official answer

Option 2

NTA final key.

Same idea in other shifts

Asked 11× in all
  1. 5 Apr 2026, Shift 2 · Q25Let y=y(x)y=y(x) be the solution of the differential equation (tan⁡x)1/2 dy=(sec⁡3x−(tan⁡x)3/2 y)dx(\tan x)^{1/2}\,dy=\left(\sec^3 x-(\tan x)^{3/2}\,y\right)dx,…HardNumerical value
  2. 8 Apr 2026, Shift 2 · Q17Let y=y(x)y = y(x) be the solution of the differential equation x1−x2 dy+(y1−x2−xcos⁡−1x)dx=0x\sqrt{1-x^2}\,dy + \left(y\sqrt{1-x^2} - x\cos^{-1}x\right)dx = 0,…MediumSingle correct
  3. 4 Apr 2024, Shift 1 · Q26Let the solution y=y(x)y=y(x) of the differential equation dydx−y=1+4sin⁡x\frac{dy}{dx}-y=1+4\sin x satisfy y(π)=1y(\pi)=1. Then…MediumNumerical value
  4. 26 Jul 2022, Shift 1 · Q11If dydx+2ytan⁡x=sin⁡x\frac{dy}{dx} + 2y \tan x = \sin x, 0<x<π20 < x < \frac{\pi}{2} and y(π3)=0y\left(\frac{\pi}{3}\right) = 0, then the maximum value of y(x)y(x)…MediumSingle correct
  5. 26 Jul 2022, Shift 2 · Q10Let the solution curve y=f(x)y=f(x) of the differential equation dydx+xyx2−1=x4+2x1−x2\frac{dy}{dx}+\frac{xy}{x^2-1}=\frac{x^4+2x}{\sqrt{1-x^2}}, x∈(−1,1)x\in(-1,1)…HardSingle correct
  6. 27 Jul 2022, Shift 1 · Q25Let y=y(x)y = y(x) be the solution curve of the differential equation…HardNumerical value
  7. 26 Jun 2022, Shift 1 · Q25Let the solution curve y=y(x)y = y(x) of the differential equation (4+x2) dy−2x(x2+3y+4) dx=0(4 + x^2)\,dy - 2x(x^2 + 3y + 4)\,dx = 0 pass through the origin. Then…MediumNumerical value
  8. 22 Jul 2021, Shift 2 · Q70Let y=y(x)y=y(x) be the solution of the differential equation cosec2x dy+2dx=(1+ycos⁡2x) cosec2x dx\mathrm{cosec}^2x\,dy+2dx=(1+y\cos2x)\,\mathrm{cosec}^2x\,dx, with…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.