JEE Main 2022 (29 Jul, Shift 1) Chemistry Q74: figure…

Question

[figure: CH3CH2CH2-Cl, a three-carbon chain bearing Cl; left arrow with AgCN, $\mathrm{C_2H_5OH-H_2O}$ gives 'A' (Major Product); right arrow with NaCN, $\mathrm{C_2H_5OH-H_2O}$ gives 'B' (Major Product)]
Considering the above reactions, the compound 'A' and compound 'B' respectively are :

Accepted Answer

Option 3: $\mathrm{CH_3CH_2CH_2-N^{+}\equiv C^{-}}$, $\mathrm{CH_3CH_2CH_2-C\equiv N}$

Answer

$\mathrm{CH_3CH_2CH_2-N^{+}\equiv C^{-}}$, $\mathrm{CH_3CH_2CH_2-N^{+}\equiv C^{-}}$

Answer

$\mathrm{CH_3CH_2CH_2-C\equiv N}$, $\mathrm{CH_3CH_2CH_2-C\equiv N}$

Answer

$\mathrm{CH_3CH_2CH_2-N^{+}\equiv C^{-}}$, $\mathrm{CH_3CH_2CH_2-C\equiv N}$

Answer

$\mathrm{CH_3CH_2CH_2-C\equiv N}$, $\mathrm{CH_3CH_2CH_2-N^{+}\equiv C^{-}}$

JEE Main 29 July 2022, Shift 1, Chemistry Q74

Same idea in other shifts