Learn

Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceOtherMediumCalculation

JEE Main 29 July 2022, Shift 1, Physics Q50

Question 50 of 90 in this shift, Physics question 20 of 30, Section A.

In an experiment to find out the diameter of wire using screw gauge, the following observations were noted : (A) Screw moves 0.5 mm on main scale in one complete rotation (B) Total divisions on circular scale = 50 (C) Main scale reading is 2.5 mm (D) 45th^{\mathrm{th}} division of circular scale is in the pitch line (E) Instrument has 0.03 mm negative error Then the diameter of wire is :

The figure, in words

Screw gauge drawn as a U-shaped frame with studs P and Q, screw thread, and circular scale showing 45 at the reference line.
  1. (1)2.92 mm
  2. (2)2.54 mm
  3. (3)2.98 mmOfficial answer
  4. (4)3.45 mm

Official answer

Option 3

NTA final key.

Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.