24:["$","div",null,{"className":"space-y-5 border-t border-rule-2 pt-8","children":[["$","h1",null,{"className":"fs-label text-signal-ink","children":["JEE Main ","28 July 2022, Shift 2",", ","Physics"," Q",30]}],["$","p",null,{"className":"text-[14px] leading-snug text-ink-3","children":["Question ",30," of ",90," in this shift, ","Physics"," question ",30," of ",30,", Section B",".",""]}],["$","div",null,{"className":"space-y-6","children":[["$","div",null,{"className":"space-y-3 text-[18px] leading-relaxed text-ink sm:text-[19px]","children":[["$","span","p0",{"className":"block whitespace-pre-line","children":[["$","span","0",{"children":"In an experiment to find acceleration due to gravity (g) using simple pendulum, time period of 0.5 s is measured from time of 100 oscillation with a watch of 1 s resolution. If measured value of length is 10 cm known to 1 mm accuracy, The accuracy in the determination of g is found to be "}],["$","span","1",{"dangerouslySetInnerHTML":{"__html":"

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JEE Main 28 July 2022, Shift 2, Physics Q30