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Friday, 9 October

JEE Main 2022 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 28 July 2022, Shift 1, Maths Q29

Question 29 of 90 in this shift, Maths question 29 of 30, Section B.

lim⁡x→0((x+2cos⁡x)3+2(x+2cos⁡x)2+3sin⁡(x+2cos⁡x)(x+2)3+2(x+2)2+3sin⁡(x+2))100x\lim_{x\to0}\left(\frac{(x+2\cos x)^3+2(x+2\cos x)^2+3\sin(x+2\cos x)}{(x+2)^3+2(x+2)^2+3\sin(x+2)}\right)^{\frac{100}{x}} is equal to __________.

Official answer

1

NTA final key (2022 Session 2).

Same idea in other shifts

Asked 2× in all
  1. 8 Jan 2020, Shift 1 · Q57lim⁡x→0(3x2+27x2+2)1/x2\lim_{x\to 0}\left(\dfrac{3x^2+2}{7x^2+2}\right)^{1/x^2} is equal to :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.