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Friday, 9 October

JEE Main 2022 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 28 July 2022, Shift 1, Maths Q20

Question 20 of 90 in this shift, Maths question 20 of 30, Section A.

The minimum value of the twice differentiable function f(x)=∫0xex−tf′(t) dt−(x2−x+1)ex, x∈Rf(x)=\int_0^x e^{x-t}f'(t)\,dt-(x^2-x+1)e^x,\ x\in\mathbf{R}, is :
  1. (1)−2e-\frac{2}{\sqrt{e}}Official answer
  2. (2)−2e-2\sqrt{e}
  3. (3)−e-\sqrt{e}
  4. (4)2e\frac{2}{\sqrt{e}}

Official answer

Option 1

NTA final key (2022 Session 2).

Same idea in other shifts

Asked 2× in all
  1. 6 Apr 2026, Shift 2 · Q18Let f:R→Rf:\mathbf{R}\to\mathbf{R} be such that f(xy)=f(x)f(y)f(xy)=f(x)f(y), for all x,y∈Rx,y\in\mathbf{R} and f(0)≠0f(0)\neq0. Let g:[1,∞)→Rg:[1,\infty)\to\mathbf{R}…HardSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.