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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceMatch the listMediumRecall

JEE Main 27 July 2022, Shift 2, Chemistry Q74

Question 74 of 90 in this shift, Chemistry question 14 of 30, Section A.

Match **List - I** with **List - II**. List - I (A) C6H5COCl\mathrm{C_6H_5COCl} →Pd−BaSO4H2\xrightarrow[\mathrm{Pd-BaSO_4}]{\mathrm{H_2}} C6H5CHO\mathrm{C_6H_5CHO} (B) CH3−CN\mathrm{CH_3-CN} →H3O+SnCl2/HCl\xrightarrow[\mathrm{H_3O^+}]{\mathrm{SnCl_2/HCl}} CH3−CHO\mathrm{CH_3-CHO} (C) C6H5CH3\mathrm{C_6H_5CH_3} →H3O+CrO2Cl2\xrightarrow[\mathrm{H_3O^+}]{\mathrm{CrO_2Cl_2}} C6H5CHO\mathrm{C_6H_5CHO} (D) C6H6\mathrm{C_6H_6} →AlCl3 (anhyd)CO, HCl\xrightarrow[\mathrm{AlCl_3\ (anhyd)}]{\mathrm{CO,\ HCl}} C6H5CHO\mathrm{C_6H_5CHO} List - II (I) Gatterman Koch reaction (II) Etard reaction (III) Stephen reaction (IV) Rosenmund reaction Choose the **correct** answer from the options given below :

The figure, in words

List-I entries are drawn reaction schemes with benzene-ring structures (benzoyl chloride, toluene, benzene) giving benzaldehyde.
  1. (1)(A) - (IV), (B) - (III), (C) - (II), (D) - (I)Official answer
  2. (2)(A) - (I), (B) - (II), (C) - (III), (D) - (IV)
  3. (3)(A) - (II), (B) - (III), (C) - (IV), (D) - (I)
  4. (4)(A) - (III), (B) - (II), (C) - (I), (D) - (IV)

Official answer

Option 1

NTA final key.