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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 27 July 2022, Shift 2, Physics Q43

Question 43 of 90 in this shift, Physics question 13 of 30, Section A.

A cyclotron is used to accelerate protons. If the operating magnetic field is 1.0 T and the radius of the cyclotron 'dees' is 60 cm, the kinetic energy of the accelerated protons in MeV will be : [use mp=1.6×10−27\mathrm{m_p}=1.6\times10^{-27} kg, e=1.6×10−19=1.6\times10^{-19} C]
  1. (1)12
  2. (2)18Official answer
  3. (3)16
  4. (4)32

Official answer

Option 2

NTA final key.