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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctMediumCalculation

JEE Main 26 July 2022, Shift 2, Physics Q32

Question 32 of 90 in this shift, Physics question 2 of 30, Section A.

In a Vernier Calipers, 10 divisions of Vernier scale is equal to the 9 divisions of main scale. When both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and 4th4^{\text{th}} Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to 1 mm. While measuring diameter of a spherical body, the body is held between two jaws. It is now observed that zero of the Vernier scale lies between 30 and 31 divisions of main scale reading and 6th6^{\text{th}} Vernier scale division exactly coincides with the main scale reading. The diameter of the spherical body will be :
  1. (1)3.02 cm
  2. (2)3.06 cm
  3. (3)3.10 cmOfficial answer
  4. (4)3.20 cm

Official answer

Option 3

NTA final key.

Chapter
Units and Measurements
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.