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JEE Main 2022 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 26 July 2022, Shift 2, Maths Q18

Question 18 of 90 in this shift, Maths question 18 of 30, Section A.

Let

X

be a binomially distributed random variable with mean 4 and variance

\frac{4}{3}

. Then,

54\,P(X\leq 2)

is equal to

(1) $\frac{73}{27}$
(2) $\frac{146}{27}$ Official answer
(3) $\frac{146}{81}$
(4) $\frac{126}{81}$

Official answer

Option 2

NTA final key.

Chapter: Probability
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.