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Saturday, 31 October

JEE Main 2022 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 26 July 2022, Shift 1, Physics Q53

Question 53 of 90 in this shift, Physics question 23 of 30, Section B.

In an experiment to determine the Young's modulus of wire of a length exactly 1 m, the extension in the length of the wire is measured as 0.4 mm with an uncertainty of ±\pm 0.02 mm when a load of 1 kg is applied. The diameter of the wire is measured as 0.4 mm with an uncertainty of ±\pm 0.01 mm. The error in the measurement of Young's modulus (ΔY\Delta Y) is found to be x×1010 Nm−2x\times10^{10}\ \mathrm{Nm^{-2}}. The value of xx is __________. (take g=10 ms−2g = 10\ \mathrm{ms^{-2}})

Official answer

2

NTA final key.

Chapter
Mechanical Properties of Solids
Topic
Elasticity
Idea tested
Error Analysis in Searle's Experiment

Same idea in other shifts

Asked 4× in all
  1. 2 Apr 2026, Shift 1 · Q27The diameter of a wire measured by a screw gauge of least count 0.0010.001 cm is 0.080.08 cm. The length measured by a scale of least count…MediumSingle correct
  2. 8 Apr 2024, Shift 1 · Q48Young's modulus is determined by the equation given by Y=49000mldynecm2Y=49000\frac{m}{l}\frac{\mathrm{dyne}}{\mathrm{cm}^2} where MM is the mass and…MediumSingle correct
  3. 16 Mar 2021, Shift 2 · Q17In order to determine the Young's Modulus of a wire of radius 0.2 cm (measured using a scale of least count = 0.001 cm) and length 1m…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.