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Saturday, 31 October

JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 25 July 2022, Shift 2, Physics Q39

Question 39 of 90 in this shift, Physics question 9 of 30, Section A.

Light wave traveling in air along x-direction is given by Ey=540 Sin π×104(x−ct)Vm−1\mathrm{E_y} = 540\, \mathrm{Sin}\, \pi \times 10^{4}(x - ct)Vm^{-1}. Then, the peak value of magnetic field of wave will be (Given c = 3×1083 \times 10^{8} ms−1^{-1})
  1. (1)18×10−718 \times 10^{-7} TTOfficial answer
  2. (2)54×10−754 \times 10^{-7} TT
  3. (3)54×10−854 \times 10^{-8} TT
  4. (4)18×10−818 \times 10^{-8} TT

Official answer

Option 1

NTA final key.

Chapter
Electromagnetic Waves
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.