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JEE Main 2022 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 25 July 2022, Shift 1, Chemistry Q89

Question 89 of 90 in this shift, Chemistry question 29 of 30, Section B.

The number of

\mathrm{sp^3}

hybridised carbons in an acyclic neutral compound with molecular formula

\mathrm{C_4H_5N}

is ______.

Official answer

0 or 1

NTA final key (2022 Session 2).

Chapter: Organic Chemistry: Some Basic Principles and Techniques
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.