JEE Main 2022 · MathsNumerical answerNumerical valueHardMulti-step

JEE Main 25 July 2022, Shift 1, Maths Q23

Question 23 of 90 in this shift, Maths question 23 of 30, Section B.

If the maximum value of the term independent of

t

in the expansion of

\left(t^2x^{\frac{1}{5}}+\frac{(1-x)^{\frac{1}{10}}}{t}\right)^{15}

x\ge0

, is

K

, then

8K

is equal to ______.

Official answer

6006

NTA final key (2022 Session 2).

Chapter: Binomial Theorem
Topic: Binomial Coefficients
Idea tested: Maximum Binomial Coefficient

Same idea in other shifts

Asked 3× in all

6 Apr 2026, Shift 1 · Q8If the coefficients of the middle terms in the binomial expansions of $(1+\alpha x)^{26}$ and $(1-\alpha x)^{28}$ , $\alpha\neq 0$ , are…EasySingle correct
8 Jan 2020, Shift 1 · Q55If a, b and c are the greatest values of $^{19}C_p$ , $^{20}C_q$ and $^{21}C_r$ respectively, then :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.